Answer:
ρ = 900 kg/m³
Explanation:
Given that
a= 20 cm
Pressure at the top ,P₁ = 105 KPa
Pressure at the bottom,P₂= 106.8 KPa
Lets take the density of the fluid = ρ kg/m³
The pressure at the bottom given as
P₂ = P₁ + ρ g a
Now by putting the values
106.8 x 1000 = 105 x 1000+ ρ x 10 x 0.2 ( g= 10 m/s²)
1000(106.8 - 105) = 2 ρ
[tex]\rho=\dfrac{106.8-105}{2}\times 1000[/tex]
ρ = 900 kg/m³
Therefore the density of the fluid will be 900 kg/m³
