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The speed of a moving bullet can be determined by allowing the bullet to pass through two rotating paper disks mounted a distance 64 cm apart on the same axle. From the angular displacement 20.3 ◦ of the two bullet holes in the disks and the rotational speed 1165 rev/min of the disks, we can determine the speed of the bullet.Find the bullet speed.

Respuesta :

Answer:

The speed of the bullet is 220.6 m/s.

Explanation:

Given that,

Distance = 64 cm

Angular displacement = 20.3°

Rotational speed = 1165 rev/min

We need to calculate the time

Using formula of angular displacement

[tex]\theta=\omega\times t[/tex]

[tex]t=\dfrac{\theta}{\omega}[/tex]

Put the value into the formula

[tex]t=\dfrac{20.3\times\dfrac{\pi}{180}}{1165\times\dfrac{2\pi}{60}}[/tex]

[tex]t=0.00290\ sec[/tex]

We need to calculate the speed of the bullet

Using formula of speed

[tex]v=\dfrac{d}{t}[/tex]

Put the value into the formula

[tex]v=\dfrac{64\times10^{-2}}{0.00290}[/tex]

[tex]v=220.6\ m/s[/tex]

Hence, The speed of the bullet is 220.6 m/s.