Answer:
[tex]2~HgO (s)\rightarrow 2~Hg (g) + O_2 (g)[/tex]
Explanation:
Mercury(II) oxide, also represented by a chemical formula [tex]HgO (s)[/tex], decomposes at relatively high temperature into its components, mercury and oxygen. Due to a high temperature, not all the resultant products are in their standard states, that is, we don't obtain liquid mercury, but rather mercury vapor/gas. However, oxygen is a gas at a temperature of around [tex]500^oC[/tex]. The equation representing this process is given below:
[tex]2~HgO (s)\rightarrow 2~Hg (g) + O_2 (g)[/tex]
