Answer:
Explanation:
Given
height [tex]h=363 m[/tex]
considering Initial velocity to be zero
using [tex]v^2-u^2=2 as[/tex]
where [tex]u=initial\ velocity[/tex]
[tex]v=final\ velocity[/tex]
[tex]s=displacement[/tex]
[tex]a=acceleration[/tex]
[tex]v^2-0=2\times 9.8\times 363[/tex]
[tex]v=84.34\ m/s[/tex]
