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Water flows from a large drainage pipe at a rate of 950 gal/min. What is this volume rate of flow in (a) m3/s , (b) liters/min, and (c) ft3/s ?

Respuesta :

Answer:

[tex]0.05997\ m^3/s[/tex]

[tex]3596.1395\ L/min[/tex]

[tex]2.11647\ ft^3/s[/tex]

Explanation:

[tex]1\ gal/min=\dfrac{1}{264\times 60}\\\Rightarrow 950\ gal/min=950\times \dfrac{1}{264\times 60}\\\Rightarrow 950\ gal/min=0.05997\ m^3/s[/tex]

Volume rate of flow is [tex]0.05997\ m^3/s[/tex]

[tex]1\ gal/min=3.78541\ L/min\\\Rightarrow 950\ gal/min=950\times 3.78541=3596.1395\ L/min[/tex]

Volume rate of flow is [tex]3596.1395\ L/min[/tex]

[tex]1\ gal/min=\dfrac{1}{7.481\times 60}\\\Rightarrow 950\ gal/min=950\times \dfrac{1}{7.481\times 60}\\\Rightarrow 950\ gal/min=2.11647\ ft^3/s[/tex]

Volume rate of flow is [tex]2.11647\ ft^3/s[/tex]