Answer:
E
Explanation:
To solve this question, we need to know the oxidation number in the compound in the question. The name of the compound is tetraoxosulphate(vi) acid. We can obviously see that the oxidation number of sulphur in this particular compound is 6.
A. Is wrong
The name of the compound is trioxosulphate(iv) ion
B. Is wrong
S2O32-
2S + 3(-2) = -2
S = +2
C.is wrong
Oxidation state there is -2
D is wrong
The oxidation number here is zero
E is correct
Oxidation number of oxygen is -2 and that of chlorine is -1
Hence:
S + 2(-2) + 2(-1) = 0
S -4 -2 = 0
S = 4+2 = +6
