Answer:
[tex]a=0[/tex] ∵ [tex]\alpha=0\ rad.s^{-1}[/tex]
Explanation:
The tangential acceleration of a cart moving at a constant speed in a circle is:
The angular velocity is constant when the circular speed is constant.
We know that the (instantaneous) tangential velocity of such object is given by:
[tex]v=r.\omega[/tex]
Now for angular acceleration we have a constant angular speed:
[tex]\alpha=0\ rad.s^{-1}[/tex]
And angular acceleration is related to tangential acceleration as:
[tex]a=r.\alpha[/tex]
[tex]\Rightarrow a=0[/tex]
The tangential acceleration of a cart moving at a constant speed in a horizontal circle is zero
The formula for calculating the tangential acceleration is expressed according to the formula shown:
[tex]a=r \alpha[/tex] where:
a is the tangential acceleration
r is the radius formed by the horizontal circle
[tex]\alpha[/tex] is the angular acceleration.
If the cart is moving at a constant speed, this shows that the angular acceleration is zero, i.e. [tex]\alpha =0rad/s^2[/tex]
Substitute this parameter into the formula above to have:
[tex]a=r \alpha\\a=r(0)\\a=0m/s^2[/tex]
Hence the tangential acceleration of a cart moving at a constant speed in a horizontal circle is zero.
Learn more here: https://brainly.com/question/11762210
