Answer:
[tex]\large \boxed{\text{8.0 cm}^{3}\cdot \text{min}^{-1}}[/tex]
Explanation:
The rate of formation of O₂ is the change in volume divided by the change in time.
For the reaction
[tex]\rm 2H_{2}O_{2}\longrightarrow \, 2H_{2}O+ O_{2} \\\text{rate} = \dfrac{\Delta V}{\Delta t } = \dfrac{\text{120 cm}^{3}}{\text{ 15 min}} = \textbf{8.0 cm}^{\mathbf{3}}\cdot \textbf{min}^{\mathbf{-1}}\\\\\text{The rate of formation of oxygen is $\large \boxed{\textbf{8.0 cm}^{\mathbf{3}}\cdot \textbf{min}^{\mathbf{-1}}}$}[/tex]
