Respuesta :

Answer:The energy of an electron in the n=3 energy state of a hydrogen atom is 2.42 x 10-19 J

Explanation:

The Calculation is in the fig below.

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Answer:

-2.42×10-19 Joules

Explanation:

Where:

R = 1.0974×107 m−1 (Rydberg constant)

h = 6.626×10−34 Jsec (Planck's constant)

c = 2.998×108 m/s (speed of light)

Rhc = 2.179×10−18 J

n = 1, 2, 3 ... (principal quantum number)

For the n = 3 level:

En =   − 2.179×10-18 J/3^2

     =   -2.42×10-19 Joules