Respuesta :
Answer:The energy of an electron in the n=3 energy state of a hydrogen atom is 2.42 x 10-19 J
Explanation:
The Calculation is in the fig below.
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Answer:
-2.42×10-19 Joules
Explanation:
Where:
R = 1.0974×107 m−1 (Rydberg constant)
h = 6.626×10−34 Jsec (Planck's constant)
c = 2.998×108 m/s (speed of light)
Rhc = 2.179×10−18 J
n = 1, 2, 3 ... (principal quantum number)
For the n = 3 level:
En = − 2.179×10-18 J/3^2
= -2.42×10-19 Joules