Answer:
The height of the ball after 2 seconds = 96 feet.
Step-by-step explanation:
Given:
The height of a golf ball hit with an initial velocity of 80 FPS is given by:
[tex]H=-16t^2+80t[/tex]
where [tex]H[/tex] represents height of the ball in feet and [tex]t[/tex] represents time in seconds.
To find the height of the ball after 2 seconds.
Solution:
In order to find the height of the ball after 2 seconds, we plugin t=2 in the given function of height.
We have:
[tex]H(t)=-16t^2+80t[/tex]
At [tex]t=2[/tex] seconds
[tex]H(2)=-16(2)^2+80(2)[/tex]
[tex]H(2)=-16(4)+160[/tex]
[tex]H(2)=-64+160[/tex]
[tex]H(2)=96[/tex]
Thus, height of the ball after 2 seconds = 96 feet.
