The circle do not intersect with the x-axis
The equation of the circle is given as:
x^2 + y^2 - 10y = -16
If the circle intersects with the x-axis, then there is a real value of x such that y = 0
So, we have:
x^2 +(0)^2 - 10(0) = -16
Evaluate the exponents and the products
x^2 = -16
Take the square root of both sides
x = ±√-16
The square root of a negative number is a complex number
This means that x has no real value when y = 0
Hence, the circle do not intersect with the x-axis
Read more about circle equations at:
https://brainly.com/question/1559324
