Width = 5.5yd
Length = 12yd
Explanation:
Area of rectangle = [tex]66yd^{2}[/tex]
Let width of the rectangle = b ,
So, length = 2b+1
Area of rectangle = (length X width) - eqn 1
Putting the value of length and width in above equation 1,
[tex]66yd^{2} = (2b+1) X b\\66yd^{2} = 2b^{2} + b\\2b^{2} +b-66 = 0\\[/tex]
On solving the equation we get,
b = 5.5yd
So, width (b) = 5.5yd
and length = 2(5.5) + 1
l = 12yd
Hence,
Width = 5.5yd
Length = 12yd
