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Let f(x) = 12x5 − 36x4 − 6x3 and g(x) = 3x2. Find f of x over g of x.

4x2 + 12x + 2
4x2 − 12x − 2
4x3 + 12x2 + 2x
4x3 − 12x2 − 2x

Respuesta :

Answer:

[tex]4x^3-12x^2-2x[/tex]

Step-by-step explanation:

Given:

[tex]f(x)= 12x^5-36x^4-6x^3[/tex]

[tex]g(x)=3x^2[/tex]

We need to find  [tex]\frac{f(x)}{g(x)}[/tex] .

Solution:

We have attached the division for your reference.

Step 1:

Now here Dividend is [tex]12x^5-36x^4-6x^3[/tex] and Divisor is [tex]3x^2[/tex] so we will multiply the Divisor with [tex]4x^3[/tex] we will get the answer as [tex]12x^5[/tex] so from dividend [tex]12x^5[/tex]  will get subtracted and the remainder will be [tex]-36x^4-6x^3[/tex] and the Quotient will be [tex]4x^3[/tex].

Step 2:

Now the Dividend is [tex]-36x^4-6x^3[/tex] and Divisor is [tex]3x^2[/tex] so we will multiply the Divisor with [tex]-12x^2[/tex] we will get the answer as [tex]-36x^2[/tex] so from dividend [tex]-36x^2[/tex]will get subtracted and the remainder will be [tex]-6x^3[/tex] and the Quotient will be [tex]4x^3-12x^2[/tex]

Step 3:

Now the Dividend is [tex]-6x^3[/tex] and Divisor is [tex]3x^2[/tex] so we will multiply the Divisor with [tex]-2x[/tex] we will get the answer as so [tex]-6x^3[/tex] from dividend [tex]-36x^2[/tex]will get subtracted and the remainder will be 0 and the Quotient will be [tex]4x^3-12x^2-2x[/tex]

Hence [tex]\frac{f(x)}{g(x)} =4x^3-12x^2-2x[/tex].

Ver imagen jitumahi76

Answer: 4x^3-12x^2-2x

Step-by-step explanation:

Given:

Step-by-step explanation: