Answer:
Therefore,
[tex]x=0\ or\ x=5[/tex]
Step-by-step explanation:
Given:
[tex]x^{2}+-5x=0[/tex]
To Solve:
x = ?
Solution:
Addition and Subtraction is explain by some examples say,
5 + 3 = 8
5 - 3 = 2
But in case,
5 + - 3 is also written as
5 -3 = 2
if it is
5 - - 3 then it becomes
5 +3 = 8
That means
"+" and "-" will become "-"
"-" and "-" will become "+"
"-" and "+" will become "-"
"+" and "+" will become "+"
Therefore,
[tex]x^{2}+-5x=0[/tex]
will become
[tex]x^{2}-5x=0[/tex]
Take common 'x' out then
[tex]x(x-5)=0\\\\x = 0\ or\ x-5=0\\\\x=0\ or\ x=5[/tex]
Therefore,
[tex]x=0\ or\ x=5[/tex]
