The probability that a house in an urban area will be burglarized is 5%. If 20 houses are randomly selected, what is the mean of the number of houses burglarized

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Answer:

The mean number of houses burglarized , in an urban area, is 1.

Step-by-step explanation:

Let X = A house in an urban area will be burglarized.

The probability that a house in an urban area will be burglarized is:

P (X) = p = 0.05

The sample size of the houses selected is, n = 20.

The random variable X follows a Binomial distribution with parameters n = 20 and p = 0.05.

The probability function of a Binomial distribution is:

[tex]P(X=x) = {n\choose x}p^{x}(1-p)^{n-x}[/tex]

The expected value of a Binomial distribution is:

[tex]E(X) = np[/tex]

Compute the expected number of houses burglarized as follows:

[tex]E(X) = np=20\times0.05=1[/tex]

Thus, the mean number of houses burglarized , in an urban area, is 1.

The mean number of houses is simply the expected number of houses selected

The mean number of houses burglarized is 1

The given parameters are:

[tex]\mathbf{n = 20}[/tex] --- number of houses

[tex]\mathbf{p = 5\%}[/tex] --- probability that a house is burglarized

The mean number of houses is calculated using the formula of expected value.

So, we have:

[tex]\mathbf{E(x) = n \times p}[/tex]

Substitute values for n and p

[tex]\mathbf{E(x) = 20 \times 5\%}[/tex]

[tex]\mathbf{E(x) = 1}[/tex]

Hence, the mean number of houses burglarized is 1

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