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2. A kayaker travels 4 miles upstream and 4 miles downstream in a total of 6 hours. In still
water, the kayaker can travel at an average speed of 2.3 mi/h.
Determine the average speed of the river's current.

Respuesta :

The average speed of the river's current is 1.49107 miles per hour

Solution:

Given that,

Upstream distance = 4 miles

Downstream distance = 4 miles

If the speed of a boat in still water is u km\hr and the speed of the stream is v km/hr then:

Speed downstream = u + v km\hr

Speed upstream = u - v km\hr

From given,

Speed in still water = 2.3 miles per hour

u = 2.3

Therefore,

speed downstream = 2.3 + v

Speed upstream = 2.3 - v

The total time is 6 hours

Therefore,

[tex]time = \frac{distance}{speed}[/tex]

Thus we get,

[tex]\frac{4}{2.3+v}+\frac{4}{2.3-v} = 6\\\\4(\frac{1}{2.3+v} + \frac{1}{2.3-v}) = 6\\\\\frac{1}{2.3+v} + \frac{1}{2.3-v} = \frac{6}{4}\\\\\frac{2.3 - v + 2.3 + v }{2.3^2 - v^2} = \frac{6}{4}\\\\\frac{4.6}{5.29-v^2} = \frac{6}{4}\\\\31.74 - 6v^2 = 18.4\\\\6v^2 = 13.34\\\\v^2 = 2.2233\\\\v = 1.49107[/tex]

Thus the average speed of the river's current is 1.49107 miles per hour

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