[tex]\therefore{\green{(B)\:15\:is\:6\% \:of\: 250.}}[/tex]
Let the required number be x.
Atq,
[tex] \implies 6\% \: of \: x = 15 \\ \implies \frac{6}{100} \times x = 15 \\ \implies \frac{3x}{50} = 15 \\ \implies 3x = 50 \times 15 \\ \implies x = \frac{50 \times 15}{3} \\ \implies x = 50 \times 5 \\ \implies x = 250[/tex]