Mug 2 can hold the most as its volume is greater than that of mug 1
Step-by-step explanation:
To find out which mug holds more let us find the volume of each mug
As we know
Height of first mug =H1= 3 in
Diameter of first mug= D1= 5.5 in
Radius of first mug = R1= [tex]\frac{5.5}{2}[/tex]
= 2.75 in
The volume of first mug M1 is V1
The formula used will be
V=πr2h
V1 will be equal to
[tex]V1=\pi r_{1} 2 h_{1} \\V1= \pi (2.75) (2) (3)\\V1= 51.81[/tex]
V1 = 51.81
Similarly
As we know
Height of second mug = H2= 4 in
Diameter of second mug = D2 = 4.5 in
Radius of second mug = R2= [tex]\frac{4.5}{2}[/tex]
= 2.25 in
The volume of second mug M2 is V2
the formula used will be
V=πr2h
V2 will be equal to
[tex]V2= \pi r_{2} 2h_{2} \\V2 = \pi (2.25)(2)(4)\\V2 = 56.52[/tex]
V2 = 56.52
So as V2(56.52) is greater than V1(51.81) so mug 2 can hold the most
Keywords: volume of cylinder
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