sirbridgeman2
contestada

A worker drives a 0.500 kg spike into a rail tie with a 2.50 kg sledgeham-
mer. The hammer hits the spike with a speed of 65.0 m/s. If one-third of
the hammer's kinetic energy is converted to the internal energy of the
hammer and spike, how much does the total internal energy increase?

Respuesta :

skyluke89

Total internal energy increases by 1760 J

Step-by-step explanation:

The kinetic energy of an object is the energy possessed by the object due to its motion.

It is calculated as

[tex]KE=\frac{1}{2}mv^2[/tex]

where

m is the mass of the object

v is its speed

For the hammer in this problem:

m = 2.50 kg

v = 65.0 m/s

So its kinetic energy is

[tex]KE=\frac{1}{2}(2.50)(65)^2=5281 J[/tex]

Then the problem says that 1/3 of the hammer's kinetic energy is converted into internal energy: therefore, the total internal energy increases by

[tex]\frac{1}{3}KE=\frac{1}{3}(5281)=1760 J[/tex]

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

aksnkj

The increase in internal energy will be 1760.42 J.

Given information:

The mass of the sledgehammer is [tex]m=2.5[/tex] kg.

The velocity of the sledgehammer is [tex]v=65[/tex] m/s.

So, the kinetic energy of the sledgehammer will be calculated as,

[tex]KE=\dfrac{1}{2}mv^2\\KE=0.5\times 2.5\times 65^2\\KE=5281.25\rm \; J[/tex]

Now, one-third of the hammer's kinetic energy is converted to the internal energy of the  hammer and spike.

So, the increase in internal energy will be calculated as,

[tex]IE=\dfrac{1}{3}KE\\IE=\dfrac{1}{3}\times 5281.25\\IE=1760.42\rm\; J[/tex]

Therefore, the increase in internal energy will be 1760.42 J.

For more details, refer to the link:

https://brainly.com/question/18461965

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