The answer of 4(2x^3 y^4 )^4/2(2x^2 y^6 )^3 after simplification will be
4 [tex]x^{6} y^{-2}[/tex]
Step-by-step explanation:
To simplify
[tex]\frac{4(2x^3 y^4 )^4}{2(2x^2 y^6 )^3}[/tex] .
Using exponential law the exponents of variables will be added when multiplied as per rule
we get
[tex]\frac{4[(2^4)(x^{3\times 4}) ( y^{4\times4} )] }{2[(2^3)(x^{2\times3} ) (y^{6\times3} )]}\\[/tex]
[tex]\frac{4[(16)(x^{12}) ( y^{16} )] }{2[(8)(x^{6} ) (y^{18} )]}\\\\\frac{64x^{12}y^{16} }{16 x^{6}y^{18} }[/tex]
Now by dividing according to exponential rule the exponents of variables will be subtracted as per rule
[tex](\frac{64}{16} ) x^{12-6} y^{16-18} \\4 x^{6} y^{-2}[/tex]
So the answer of 4(2x^3 y^4 )^4/2(2x^2 y^6 )^3 after simplification will be
4 [tex]x^{6} y^{-2}[/tex]
Keywords: Algebra
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