Answer:
693 N.
Explanation:
Given that
m = 1100 kg
Initial velocity ,u = 27 m/s
Final velocity ,v= 0 m/s
s= 578 m
Lets take the acceleration = a
We know that
v ²=u² + 2 a s
0 ²=27² + 2 x a x 578
[tex]a=\dfrac{-27^2}{2\times 578}\ m/s^2[/tex]
[tex]a=-0.63 \ m/s^2[/tex]
We know that
Force = Mass x Acceleration
F= 1100 x (-0.63) N
F= - 693 N
Therefore the force is 693 N.
