Acceleration: [tex]a=\frac{2(vt-s)}{t^2}[/tex]
Step-by-step explanation:
For an object in uniformly accelerated motion, we can use the so-called SUVAT equations.
One of them is:
[tex]s=vt-\frac{1}{2}at^2[/tex]
where
s is the displacement
v is the final velocity
t is the time
a is the acceleration
Here we want to re-arrange the equation to find the acceleration. We start by adding [tex]-vt[/tex] on both sides of the equation:
[tex]s-vt=-\frac{1}{2}at^2[/tex]
Now we change sign on both sides:
[tex]\frac{1}{2}at^2=vt-s[/tex]
And finally we multiply by 2 and divide by [tex]t^2[/tex] on both sides, so we get:
[tex]a=\frac{2(vt-s)}{t^2}[/tex]
Learn more about accelerated motion:
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