Answer:
The freezing point is -30.0°C
Explanation:
Supposing the antifreeze to be ethylene glycol, C2H6O2.
Take a hypothetical sample of 2000 g of radiator fluid. Then there is 1000 g each of water and ethylene glycol:
(1000 g C2H6O2) / (62.06810 g C2H6O2/mol) = 16.111 mol C2H6O2
So the molality is 16.111 m.
(1.86 °C/m) x (16.111 m) = 30.0 °C change
0°C - 30.0°C = -30.0°C
