Answer:
Explanation:
Given
Diameter of cylindrical is [tex]d=12\ mm[/tex]
There is excess Pressure in the cylindrical jet which can be calculated by using Equilibrium free body Diagram of an element of jet
excess Pressure force will balance the Surface tension force of water jet
[tex]\Delta P\times Area=Surface\ tension \times length[/tex]
[tex]\Delta P\cdot 2R\delta l=\sigma \times 2\delta l[/tex]
where [tex]\sigma =[/tex]surface tension of water
[tex]\Delta P=[/tex]excess Pressure
R=radius
[tex]\delta l=[/tex]length of element
therefore [tex]\Delta P=\frac{\sigma }{R}[/tex]
Surface Tension of water is [tex]\sigma =7.34\times 10^{-2}\ N/m[/tex]
[tex]\Delta P=\frac{7.34\times 10^{-2}}{6\times 10^{-3}}[/tex]
[tex]\Delta P=12.23\ Pa[/tex]
