Answer:
Option 4 is correct (72 seconds)
Explanation:
Option 4 is correct (72 seconds)
The formula we are going to use is:
[tex]ln\frac{A}{A_o}=-kt[/tex]
Where:
A is the final concentration
A_o is the initial concentration
k is the constant
t is the time
Half-Life=0.693/k
Half-life in our case=24 seconds
k=0.693/24
k=0.028875 s^-1
Since the concentration is decreased by 87.5 % which means only 12.5%(100-87.5%) is left.
The ratio [tex]A/A_o[/tex] will become 0.125
[tex]ln 0.125=-0.028875*t\\t=72.015\ seconds[/tex]
t≅ 72 seconds
