You can count the number of total favorable cases and take its ratio with the count of total cases to get the intended probability.
The probability of getting exactly two heads is given by
Option C : 3/8
Since each coin can have 2 outcomes (head and tail), and for each of them, second coin has 2 outcome and same for 3rd coin, thus, we have in total [tex]2 \times 2 \times 2 = 8[/tex]
Since we need exactly 2 heads, thus, total cases are:
(H,H,T), (H,T,H), (T,H,H)
(total 3 cases)
Thus, the probability for needed event is:
[tex]p = \dfrac{\text{Count of favorable cases}}{\text{Count of total cases}} = \dfrac{3}{8}[/tex]
Thus,
The probability of getting exactly two heads is given by
Option C : 3/8
Learn more about probability here:
brainly.com/question/1210781