Answer:
So the slope of this function is [tex]\frac{1}{2}[/tex] and the y-intercept is [tex]\frac{3}{2}[/tex]
Step-by-step explanation:
A first order function has the following format:
[tex]y = ax + b[/tex]
In which a is the slope and b is the y-intercept, that is, the value of y when x = 0.
We have the following equation:
[tex]-x + 2y = 3[/tex]
We just have to rewrite this equation
[tex]2y = x + 3[/tex]
[tex]y = \frac{x+3}{2}[/tex]
[tex]y = \frac{x}{2} + \frac{3}{2}[/tex]
Which means that
[tex]a = \frac{1}{2}, b = \frac{3}{2}[/tex]
So the slope of this function is [tex]\frac{1}{2}[/tex] and the y-intercept is [tex]\frac{3}{2}[/tex]
