Answer:
the equation of this trend line is [tex]K\:=\:-2J+28[/tex]
Step-by-step explanation:
Considering some of the points on the trend line
As variable J represents x-axis, and variable K represents y-axis.
As the y-intercept can be obtained by putting x = 0.
So, when when x = 0, y = 28
Thus, the y-intercept = 28
As the slop intercept form is
[tex]y\:=\:mx+b[/tex]
The slope can be obtained using the formula
[tex]m=\frac{y_{2} -y_{1}}{x_{2} -x_{1}}[/tex]
Taking any two points, let say
[tex]m\:=\:\frac{20-24\:}{4-2}\:[/tex]
[tex]m=-\frac{4}{2}[/tex]
[tex]m=-2[/tex]
The y-intercept = b = 28
As J represents the x-axis values, and K represents y-axis values
So, rewriting the slope intercept form
[tex]y\:=\:mx+b[/tex]
[tex]K\:=\:mJ+b[/tex]
[tex]K\:=\:-2J+28[/tex]
Therefore, the equation of this trend line is [tex]K\:=\:-2J+28[/tex]
Keywords: slope intercept form, point, graph
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