Respuesta :
Answer:
The minimum force that must be exerted by the mechanic at the end of a 30 cm-long wrench to loosen the nut is 110N
Explanation:
Torque = Fd sin θ
For a torque, the minimum force must be applied perpendicular to the lever arm, so that θ = 90° and sin θ = sin 90° = 1
Torque = 33 N.m
F = Force applied = ?
d = 30 cm = 0.3 m
F = Torque/d = 33/0.3 = 110 N
Answer:
110 N.
Explanation:
Torque = F * (d sin θ)
Where,
F = force applied
d = distance perpendicular to the force applied.
Minimum force applied is at 90° to the force. Therefore,
Torque = F * (d sin 90°)
33 = F * (0.3 * 1)
= 33/0.3
= 110 N.
