Waves are observed to splash upon the rocks at the shore every 6.0

seconds. The distance measured from crest to adjacent crest is 8.0

m. The distance measured from the lowest to the highest point on

the medium is 10.0 m. Determine the frequency, wavelength and

speed of these waves.

Respuesta :

Explanation:

Given that,

Waves are observed to splash upon the rocks at the shore every 6.0  seconds

The distance measured from crest to adjacent crest is 8.0  m

The distance measured from the lowest to the highest point on  the medium is 10.0 m.

We need to find the frequency, wavelength and  speed of these waves. We know that the distance measured from crest to adjacent crest is called wavelength of a wave. So, [tex]\lambda=8\ m[/tex]

The inverse of time taken by the wave is called its frequency,

[tex]f=\dfrac{1}{T}[/tex]

[tex]f=\dfrac{1}{6\ s}[/tex]

f = 0.167 Hz

The speed of a wave is the product of frequency and wavelength. It is given by :

[tex]v=f\times \lambda[/tex]

[tex]v=0.167 \times 8[/tex]

v = 1.336 m/s

Hence, this is the required solution.

The frequency of the wave is 0.167 Hz, the wavelength is 8m and the speed is 1.336 m/s.

Characteristics of a wave:

Given that waves are observed to splash upon the rocks at the shore every 6.0 seconds. So the time period of the wave is T = 6s.

The wavelength of the wave is λ = 8.0 m

To find the velocity of the wave, we need to find the frequency first, since velocity, frequency, and wavelength are interrelated.

The frequency is defined as the inverse of the time period of the wave:

[tex]f = \frac{1}{T}[/tex]

where T is the time period.

so,

[tex]f = \frac{1}{6}[/tex]

f = 0.167 Hz

The relation between velocity, frequency, and wavelength is given by :

v = f×λ

v = 0.167×8

v = 1.336 m/s

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