Answer:
f(2)= 5
f^-1(1)=2
f^-1(f(2))= 10
Step-by-step explanation:
[tex]f(x)= 5x , f^{-1}(x)= 2x[/tex]
first we need to find f(2), plug in 2 for x in f(x)
[tex]f(x)= 5x \\f(2)= 5(2)= 10[/tex]
[tex]f^{-1}(x)= 2x[/tex]
To find f^-1(1) , we plug in 1 for x in f inverse
[tex]f^{-1}(x)= 2x\\f^{-1}(1)= 2(1)= 2[/tex]
now we find f^-1(f(2))
we know f(2)= 10
so we find f^-1(10)
[tex]f^{-1}(x)= 2x\\f^{-1}(10)= 2(10)= 20[/tex]
