Answer:
20.7278 m
Explanation:
Reaction time [tex]t_1=0.27\ s[/tex]
Distance traveled in the reaction time
[tex]s=vt\\\Rightarrow s=\dfrac{91}{3.6}\times 0.27=6.825\ m[/tex]
Reaction time [tex]t_2=1.09\ s[/tex]
Distance traveled in the reaction time
[tex]s=vt\\\Rightarrow s=\dfrac{91}{3.6}\times 1.09[/tex]
If at both times the deceleration is the same then the difference in distance is
[tex]\dfrac{91}{3.6}\times 1.09-6.825=20.7278\ m[/tex]
The distance traveled farther is 20.7278 m