Answer:
20573.67N
Explanation:
Given;
mass (m) of the car = 2130kg
angle of inclination Θ = 15⁰
The normal force (F) on the car is given by
F = mgcosΘ
where g is the acceleration due to gravity.
Taking g as 10[tex]m/s^{2}[/tex] and substituting the values of m and Θ into the equation. We have;
F = 2130 x 10 x cos 15⁰
F = 2130 x 10 x 0.9659
F = 20573.67N
Therefore the normal force on the car is 20573.67N
