Answer:
the height of the triangular base of the pyramid is Five-halves StartRoot 3 EndRootunits = (5/2)√3 units
Step-by-step explanation:
An image of the sketch of the equilateral triangle is attached to this solution.
The height of the equilateral triangle base of the pyramid divides the equilateral triangle into two equal parts as shown in the image. And it also dimensions the bottom side into two equal parts of 5/2 units each.
Let this height be called h
Using Pythagoras theorem,
5² = h² + (5/2)²
s² = h² + (s
5²/4)
h² = 5² - (5²/4)
h² = 75/4
h = √(75/4)
h = (5/2)√3 units
Hope this Helps!!!
