Answer: The partial pressure of oxygen on the plane is 138.6 mmHg
Explanation:
To calculate the partial pressure of the gas, we use the equation given by Raoult's law, which is:
[tex]p_{A}=p_T\times \chi_{A}[/tex]
where,
[tex]p_A[/tex] = partial pressure of oxygen gas = ?
[tex]p_T[/tex] = total pressure = 660 mmHg
[tex]\chi_A[/tex] = mole fraction of oxygen gas = 21 % = 0.21
Putting values in above equation, we get:
[tex]p_{O_2}=660mmHg\times 0.21\\\\p_{O_2}=138.6mmHg[/tex]
Hence, the partial pressure of oxygen on the plane is 138.6 mmHg
