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A 6.8-kilogram block is sliding down a horizontal, frictionless surface at a constant speed of 6.0 meters per second. The kinetic energy of the block is approximately

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rafaleo84

Answer:

Ek = 122.4 [J]

Explanation:

This is a problem related to energy conservation, for this particular case kinetic energy is calculated with the following expression

[tex]E_{k}=\frac{1}{2}*m*v^{2}[/tex]

where:

m = mass = 6.8[kg]

v = velocity = 6 [m/s]

Now replacing:

[tex]E_{k} = \frac{1}{2}*6.8*(6)^{2}\\ E_{k} = 122.4[J][/tex]

Note: The unit for energy is the Joule

ajeigbeibraheem

The kinetic energy of the block is approximately 122 Joules

Given that the kinetic energy of the object in motion is sliding with a mass of 6.8 kilograms and a constant speed 6.0 meter per second.

The kinetic energy of an object can be determined by using the formula:

[tex]\mathbf{K.E = \dfrac{1}{2} \times m \times v^2}[/tex]

[tex]\mathbf{K.E = \dfrac{1}{2} \times 6.8 kg \times (6.0 \ m/s)^2}[/tex]

[tex]\mathbf{K.E = 3.4 kg \times (36 \ m/s)^2}[/tex]

K.E = 122.4 kg m²/s²

K.E = 122 Joules

Learn more about Kinetic energy here:

https://brainly.com/question/12669551?referrer=searchResults

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