Answer:
V₂ = 46.99 μL.
Explanation:
Given that
V₁ = 45.1 μL
T₁ = 24.7°C = 273 + 24.7 = 297.7 K
T₂ = 37.2°C = 273+37.2=310.2 K
Lets take ,The final volume = V₂
We know that ,the ideal gas equation
If the pressure of the gas is constant ,then we can say that
[tex]\dfrac{V_2}{V_1}=\dfrac{T_2}{T_1}[/tex]
[tex]{V_2}=V_1\times \dfrac{T_2}{T_1}[/tex]
Now by putting the values in the above equation we get
[tex]{V_2}=45.1\times \dfrac{310.2}{297.7}\ \mu \ L[/tex]
V₂ = 46.99 μL.
The final volume will be 46.99 μL.
