Answer:
[tex]F_w=9408\ N[/tex]
Weight of the truck=9408 N
Step-by-step explanation:
Boat is experiencing the buoyant force as it is in the water and is sinking
According to the force balance in y direction. As both is floating, two forces balance each other:
[tex]F_b-F_w=0[/tex]
where:
[tex]F_b[/tex] is the buoyant force
[tex]F_w[/tex] is the weight=mg
[tex]F_b=F_w[/tex] Eq (1)
Buoyant force is equal to the mass of water displaced * gravitational acceleration.
[tex]F_b=m_{water\ displaced}*g\\F_b=\rho Vg\\[/tex]
Taking density of water to be 1000 Kg/m^3
[tex]F_b=1000*(6*4*4*10^{-2})*9.8\\F_b=9408 N[/tex]
From Eq(1):
[tex]F_w=9408\ N[/tex]
Weight of the truck=9408 N
