Answer:
138.6 g of C₂HF₃O₂ have 38.9 g of O
Explanation:
Trifluoroacetic acid → C₂HF₃O₂
Molar mass = Mass of C . 2 + Mass of H + Mass of F . 3 + Mass of O .2
Molar mass = 12 . 2 + 1 . 1 + 19 . 3 + 16 . 2 = 114 g /mol
1 mol of C₂HF₃O₂ has:
2 moles of C
1 mol of H
3 moles of F
2 moles of O
If we state the relation in mass by g we say:
114 g of C₂HF₃O₂ have 24g of C, 1 g of H, 57 g of F and 32 g of O
Let's make a rule of three:
32 g of O are contained in 114 g of C₂HF₃O₂
38.9 g of O may be contained in (38.9 . 114) / 32 = 138.6 g
The mass of the trifluoroacetic acid sample. is 138.6 g
Since
Trifluoroacetic acid → C₂HF₃O₂
So,
Molar mass = Mass of C . 2 + Mass of H + Mass of F . 3 + Mass of O .2
= 12 . 2 + 1 . 1 + 19 . 3 + 16 . 2 = 114 g /mol
Now we know that
1 mol of C₂HF₃O₂ has:
2 moles of C
1 mol of H
3 moles of F
2 moles of O
Now
114 g of C₂HF₃O₂ have 24g of C, 1 g of H, 57 g of F and 32 g of O
Now
32 g of O are comprised in 114 g of C₂HF₃O₂
So,
= (38.9 . 114) / 32
= 138.6 g
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