Answer:
[tex]MgAl_2O_4[/tex]
Explanation:
Given that:- The percentage by mass of oxygen in the compound is 44.98 %
Form the formula, it can be seen that:-
4 moles of oxygen atom are present in 1 mole of the compound.
Molar mass of oxygen = 16 g/mol
Mass of 4 moles of oxygen = 4 mol x 16 g/mol = 64 g
Mass of the compound = [tex]\frac{64}{44.98}\times 100[/tex] = 142 g
Mass of aluminum + Mass of magnesium = Total mass - Mass of oxygen = 142 g - 64 g = 78 g
Molar mass of aluminium = 27 g/mol
Moles of aluminum = y moles
Molar mass of magnesium = 24 g/mol
So, 24x + 27 y = 78
Thus, x = 1 and y = 2 (One solution )
Thus, the formula is [tex]MgAl_2O_4[/tex]
