Absolute pressure: [tex]1.89\cdot 10^5 Pa[/tex]
Explanation:
The total pressure at a certain depth of a liquid is given by
[tex]p=p_0 + \rho g h[/tex]
where
[tex]p_0 = 1.01\cdot 10^5 Pa[/tex] is the atmospheric pressure
[tex]\rho[/tex] is the density of the liquid
g is the acceleration of gravity
h is the depth of the liquid
For the liquid in this problem, we have
[tex]\rho=997 kg/m^3[/tex] is the density
[tex]g=9.8 m/s^2[/tex]
h = 9 m is the column of liquid
Substituting, we find
[tex]p=1.01\cdot 10^5 + (997)(9.8)(9)=1.89\cdot 10^5 Pa[/tex]
Learn more about pressure in a fluid:
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