Answer:
[tex]1.7\times 10^{-1}\ m^3[/tex]
Explanation:
[tex]\rho[/tex] = Density of water = 1000 kg/m³
Mass is given by
[tex]m=\rho V\\\Rightarrow m=1000V[/tex]
[tex]Q=mL\\\Rightarrow Q=1000V336000\\\Rightarrow Q=336\times 10^{6}V[/tex]
Energy used is
[tex]9\times 1200=10800\ W[/tex]
[tex]Q=10800\times 1.5\times 3600=58320000\ J[/tex]
[tex]336\times 10^{6}V=58320000\\\Rightarrow V=\dfrac{58320000}{336\times 10^{6}}\\\Rightarrow V=0.173571428571\ m^3[/tex]
The volume of water is [tex]1.7\times 10^{-1}\ m^3[/tex]
