Answer:
32.11 g/mol
Explanation:
Given;
32S => 91.65%, 31.97g/mol
33S => 2.4%, 32.97g/mol
34S => 5.95%, 33.97g/mol
The molar mass of sulfur in the sample is the weighted average of the molar masses of its isotopes based on the percentage abundances.
i.e
molar mass = ([tex]\frac{91.65}{100}[/tex] x 31.97) + ([tex]\frac{2.4}{100}[/tex] x 32.97) + ([tex]\frac{5.95}{100}[/tex] x 33.97)
molar mass = (0.9165 x 31.97) + (0.024 x 32.97) + (0.0595 x 33.97)
molar mass = (29.30) + (0.79) + (2.02)
molar mass = 32.11g/mol
Therefore the molar mass of sulfur in the sample is 32.11 g/mol
