A passenger train travels 392 mi in the same time that it takes a freight train to travel 322 mi. If the passenger train travels 20 mi/h faster than the freight train, find the speed of each train.

Respuesta :

Answer:

Explanation:

Given

distance traveled by  Passenger train is [tex]d_1=392\ mi[/tex]

distance traveled by  Freight train is [tex]d_2=322\ mi[/tex]

Both take same time to travel

suppose speed of freight train is x mph

so speed of passenger train is 20+x mph

we know time[tex]=\frac{distance}{speed}[/tex]

[tex]t=\frac{392}{20+x}=\frac{322}{x}[/tex]

[tex]392x=322x+322\times 20[/tex]

[tex]70x=322\times 20[/tex]

[tex]x=92\ mph[/tex]

speed of passenger train [tex]x+20=112\ mph[/tex]