Answer:
5 trips
Step-by-step explanation:
Note that the weight and volume of the load must not exceed the given maximum.
Volume of load = 19.8m^3
Density of load = 650kg/m^3
Mass of load = 19.8 × 650 = 12,870 kg
Given limits.
Volume = 4m^3
Mass = 3700kg
Assuming the truck is to carry 4m^3 of the load.
The mass of 4m^3 of the load is = 4 × 650 = 2600kg
Mass = 2600kg < 3700kg
Therefore it satisfies both conditions.
The number of trip the truck would make is;
N = total volume of load/ volume per trip
N = 19.8/4
N = 4.95
N = 5 trips