Answer:
Explanation:
Given
time taken [tex]t=2\ s[/tex]
Speed acquired in 2 sec [tex]v=42\ m/s[/tex]
Here initial velocity is zero [tex]u=0[/tex]
acceleration is the rate of change of velocity in a given time
[tex]a=\frac{v-u}{t}[/tex]
[tex]a=\frac{42-0}{2}=21\ m/s^2[/tex]
Distance travel in this time
[tex]s=ut+0.5at^2[/tex]
where
s=displacement
u=initial velocity
a=acceleration
t=time
[tex]s=0+\0.5\times 21\times (2)^2[/tex]
[tex]s=42\ m[/tex]
so Jet Plane travels a distance of 42 m in 2 s
