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The complete Question:
Keenan gives Tisha half of his strawberries. Tisha keeps 4 of the strawberries she got from Keenan and gives the rest to Suvi.
a) Write an expression for the number of strawberries Tisha gives to Suvi. Use k for the number of strawberries Keenan started with.
b) Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.
Answer:
Part a)
An expression for the number of strawberries Tisha gives to Suvi will be: [tex]n=\frac{k}{2} -4[/tex]
Part b)
Keenan could not have started with 6 strawberries
Step-by-step explanation:
Part a) Write an expression for the number of strawberries Tisha gives to Suvi. Use k for the number of strawberries Keenan started with.
Let [tex]k[/tex] be the total number of strawberries which Keenan has.
So,
[tex]\frac{k}{2}[/tex] is the number of strawberries Keenan gave to Tisha.
As Tisha keeps 4 strawberries and gives the rest to Suvi. Let [tex]n[/tex] be the number of strawberries which Suvi has.
So,
[tex]n=\frac{k}{2} -4[/tex]
[tex]\frac{k}{2}=n+4[/tex]
[tex]k=2n+8[/tex]
Therefore, an expression for the number of strawberries Tisha gives to Suvi will be: [tex]n=\frac{k}{2} -4[/tex]
b) Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.
Considering the expression for the number of strawberries Tisha gives to Suvi
[tex]n=\frac{k}{2} -4[/tex]
Putting [tex]k = 6[/tex] in the expression
[tex]n=\frac{6}{2} -4[/tex]
Solving the expression
[tex]n=3-4[/tex] ∵ [tex]\mathrm{Divide\:the\:numbers:}\:\frac{6}{2}=3[/tex]
[tex]\mathrm{Subtract\:the\:numbers:}\:3-4=-1[/tex]
[tex]n=-1[/tex]
So, Keenan would have started with 6 strawberries, then Suvi would have -1 strawberries. Since, strawberries cannot be negative as Suvi cannot have negative number of strawberries.
Therefore, Keenan could not have started with 6 strawberries.
Keywords: word problem, expression
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