Answer:
[tex]5.9Nm^2/C[/tex]
Step-by-step explanation:
We are given that
Length of rectangle sheet=l=0.4 m
Breadth of rectangle sheet=b=0.6 m
Electric field=E=71.7 N/C
Angle[tex]=20^{\circ}[/tex]
The angle between electric field vector and area vector=[tex]\theta=90-20=70degree[/tex]
We have to find the magnitude of electric flux passing through the sheet.
Area of rectangle sheet=[tex]l\times b=0.4\times 0.6=0.24 m^2[/tex]
Magnitude of electric flux passing through the sheet=[tex]EAcos\theta=71.7\times 0.24cos70[/tex]
Magnitude of electric flux passing through the sheet=[tex]5.9Nm^2/C[/tex]
