Respuesta :
Answer:
t = 18 s
Explanation:
given,
decomposition of the material = 40 %
Remaining percentage of the material = 100 -40 = 60 %
k = 0.0284 sec⁻¹
Using equation of first order of decomposition
[tex]\dfrac{[A]}{[A_0]}=e^{-kt}[/tex]
A is the material left after decomposition
A_0 is the initial size of material before decomposition.
[tex]\dfrac{0.6[A_0]}{[A_0]}=e^{-kt}[/tex]
[tex]0.6=e^{-kt}[/tex]
[tex] -kt = ln (0.6)[/tex]
[tex] -0.0284 t = -0.5108[/tex]
[tex]t = \dfrac{0.5108}{0.0284}[/tex]
t = 18 s
Time taken to decompose 40% is equal to 18 s.
