Propane gas reacts with oxygen gas to give carbon dioxide gas and water vapor (gas). If you mix propane and oxygen in the correct stoichiometric ratio, and if the total pressure of the mixture is 300 mm Hg, what are the partial pressures of propane and oxygen? If the temperature and volume do not change, what is the pressure of the water vapor after reaction?

Respuesta :

Answer:

partial pressures of propane =51mmHg

partial pressures of oxygen = 249mmHg

Pressure of water vapor = 171mmHg

Explanation:

The concept of raoult's law of ideal solution was used as shown in the attached file.

Ver imagen olumidechemeng

Propane gas reaction.

As propane gas is a three-carbon alkali. It has a standard temperature and pressure. It can be compressed to a transport liquid. As per, the gas reacts with the air that is oxygen, and gives carbon dioxide. We mix's it with the correct ratio then the pressure mix is equal to 300 mm

Answer is a partial pressure of propane gas 51mmHg and a part of the oxygen gas to be 249 mm.

The propane gas is mixed with the oxygen gas and the gas reacts to give out carbon dioxide and thus if measuring their correct stoichiometric ratio.

The gas produces a total pressure mix of 300 mg Hg and thus partial pressure is around 51 and that for oxygen is 249 mm.

Partial pressure of gas 51 mmHg and a part of the oxygen gas to be 249 mm hg. That of water vapors of 171 mmHg.

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